a.blue.wave.of.bass Posted November 30, 2005 Report Share Posted November 30, 2005 Hi, I got a really good idea for a custom guitar but it needs a crucial piece of information. I need to know how much voltage a guitar puts out as it leaves the jack. The hottest pickup (though it's measured in ohms, I know, so maybe it's irrelevant) is a Gibson super ceramic 500T The others are a Fender TexMex and a Fender hot noiseless. I really don't know much about how electronics work, just how to wire it, outside of grounding wires run a current and leads transfer "information." Quote Link to comment Share on other sites More sharing options...
Paul Marossy Posted November 30, 2005 Report Share Posted November 30, 2005 Most hot humbucking pickups are in the range of 1 to 1.2 volts, peak-to-peak. Not sure about single coils... Quote Link to comment Share on other sites More sharing options...
crafty Posted December 1, 2005 Report Share Posted December 1, 2005 Most hot humbucking pickups are in the range of 1 to 1.2 volts, peak-to-peak. Not sure about single coils... ← ? The hottest passives are usually at less than 500 millivolts! Quote Link to comment Share on other sites More sharing options...
lovekraft Posted December 1, 2005 Report Share Posted December 1, 2005 Since the guitar's signal decays rapidly and exponentially from the pick attack, you could easily both be right, and simply talking about attack peaks versus nominal sustained levels. FWIW, F/X wiz Zachary Vex says he tweaks his circuits using a 200mV P-P signal generator, which still sounds a little hot to me, but it's hard to argue with genius! For reference, consumer line level (post-preamp) is only ~2V P-P max (@600 ohms). Any particular reason why the voltages are important? Quote Link to comment Share on other sites More sharing options...
unsane Posted December 1, 2005 Report Share Posted December 1, 2005 i'm going to take a wild stab in the dark here and say he's thinking of wiring up a speedometer of sorts controlled by output voltage Quote Link to comment Share on other sites More sharing options...
daveq Posted December 1, 2005 Report Share Posted December 1, 2005 I really don't know much about how electronics work, just how to wire it, outside of grounding wires run a current and leads transfer "information." There are lots of very helpful and experienced people here who could point you in the right direction. Please don't be offended but that last line has me thinking your project might benefit from a little more help than the answer to this quesiton. Electronics can be tricky in that you can spend months going down the wrong road without even knowing it. The old saying "I know just enough to be dangerous" applies. Just trying to help. Quote Link to comment Share on other sites More sharing options...
Paul Marossy Posted December 1, 2005 Report Share Posted December 1, 2005 (edited) I guess I should have been more clear - 1 to 1.2V maximum peak to peak voltage. This would be immediately after hitting a good and strong E chord. 500mV is more like an averaged output, AFAIK. EDIT: Check out this little article - http://www.muzique.com/lab/pick.htm Edited December 1, 2005 by Paul Marossy Quote Link to comment Share on other sites More sharing options...
JohnH Posted December 1, 2005 Report Share Posted December 1, 2005 Just to be clear; when talking about 1V 'peak to peak', does that mean a signal that goes from +1V to -1V, or +0.5V to -0.5V? John Quote Link to comment Share on other sites More sharing options...
lovekraft Posted December 1, 2005 Report Share Posted December 1, 2005 OK, IIRC, the convention is as follows - peak to peak is twice the peak positive amplitude (for a sine wave), while rms is .707*peak positive amplitude (again, for a sine wave). Or , to make it simple, 1 V P-P is 500mV P, or 353.5Vrms. That Jack Orman article Paul linked to should make evrrything pretty clear. If we had some idea what you were trying to do, it would be a lot easier to address your question. Quote Link to comment Share on other sites More sharing options...
Paul Marossy Posted December 2, 2005 Report Share Posted December 2, 2005 Try not confuse current with voltage. You gotta compare apples to apples. Quote Link to comment Share on other sites More sharing options...
a.blue.wave.of.bass Posted December 2, 2005 Author Report Share Posted December 2, 2005 I'm planning on putting a voltmeter in the guitar (non-digital) so that when a note is played the dial moves, but I'm wondering if that is possible. I am under the impression that the variation in frequency put out by the amp is transferred through the cord by varying voltage, since the pickups work by fluctuations in the electromagnetic signals in the strings, so would this work, or would the dial just stay peaked as long as the guitar is plugged in (I don't have a preamp). Would it work? Quote Link to comment Share on other sites More sharing options...
lovekraft Posted December 2, 2005 Report Share Posted December 2, 2005 You'll need an active buffer or gain stage to drive the voltmeter, to avoid loading the pickups and making everything sound wretched. Quote Link to comment Share on other sites More sharing options...
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