Before PSW's last reply, I was looking around to see if I could find away to calculate how much wire I would need of a given gauge to get 8 ohms. I found this page: AWG Table.
I measured the approximate dimensions of the bobbin to convert the number of turns I counting into an approximate length, then used that table to calculate the theoretical resistance of my failed coil. It came out a little short, but I didn't factor in the fact that windings get longer as you go. Plus I measured with a riciulously cheap DMM which show about 0.2 to 0.4 ohms when you just touch the two probes together. So if I were more careful in my calculations & measurements, the numbers probably would've turned out just about right.
Also, though it requires a bit more thought, you can use the diameter of the wire and the dimensions of the core to figure out about what the physical dimensions of the end result will be to give you the appropriate resistance.
So based on some rough guestimates, I don't think I would fit enough windings of 0.2mm in 3mm of space on my bobbin and still have the pickup case fit over it. I would probably either need about 5mm of thickness with the 0.2, or go down to 33 AWG or even 0.18 to fit it in the 3mm space. I think I'm going to try some 33 AWG and try blocking it most of the way to see how it goes.
I'll take some pics along the way so that with any luck we can have a working example of a pickup-to-driver conversion. Already removed the old wire from the bobbin, but that's a pretty self explanatory part of the process.
**EDIT**
Question about batteries.... I'm thinking about making a pack of NiMH rechargeables. A 9V just doesn't seem like it would last long enough to mess with. Which would be better? 6x AA, or a couple 9v's in parallel?
There are AA NiMH's rated at 2000mAh, while the best 9V NiMH's are around 200mAh. But if the AA's ALL drop to 1V, then there's a problem (probably).
Any thoughts on this? How much current does one of these things typically draw?