albertop Posted September 20, 2004 Report Share Posted September 20, 2004 Hello, I would like to convert two 500k pots to 250k so I can use them as tone controls, is there any way to do this?. My problem id that here in my country I can only get extremely low quality pots, they scratch even when new, and a friend gave me a couple of pots and I would like to use. I read that the difference is notorius between the 500k and the 250k for a tone control. thanks a lot. Quote Link to comment Share on other sites More sharing options...
lovekraft Posted September 20, 2004 Report Share Posted September 20, 2004 You can add a 250K resistor in parallel with the fixed terminals of the pot, but it will alter the response of the pot. Or you could use a smaller cap to get the same frequency response without chaging the pots. Quote Link to comment Share on other sites More sharing options...
mattdowney Posted September 20, 2004 Report Share Posted September 20, 2004 or just buy new pots haha i wouldent fool around with modifying pots, it would be dificult, and you would loose response and tone of the pot. just buy some new ones, my local guitar shop has these cheap 5$ pots that are amazing i use them on all of my guitars. Quote Link to comment Share on other sites More sharing options...
lovekraft Posted September 20, 2004 Report Share Posted September 20, 2004 Matt, no offense, but try to stay with the group here. Did you not read this? My problem id that here in my country I can only get extremely low quality pots Somehow, I don't think Alberto has the option of scooting down to the Guitar center for new pots. Quote Link to comment Share on other sites More sharing options...
Stalefish Posted September 21, 2004 Report Share Posted September 21, 2004 You can add a 250K resistor in parallel with the fixed terminals of the pot, but it will alter the response of the pot. Or you could use a smaller cap to get the same frequency response without chaging the pots. Erm... Isn't that a 500k resistor in parallel with the 500k pot terminals? Using that [(R1)*(R2)]/[R1+R2] equation, 2 500k resistors in parallel should give you an equivalent of 250k.. Anyway, to add, I've tried this before and it does alter the response quite drastically like what Lovekraft mentioned.. No harm trying, though.. You could always just remove the resistor if you're not happy.. Quote Link to comment Share on other sites More sharing options...
lovekraft Posted September 21, 2004 Report Share Posted September 21, 2004 Erm... Isn't that a 500k resistor in parallel with the 500k pot terminals? Yeah, it is! Thanks, Stalefish, sometimes my math skills fail me completely. Quote Link to comment Share on other sites More sharing options...
Stalefish Posted September 22, 2004 Report Share Posted September 22, 2004 No worries.. For a while I was afraid that my maths was screwed.. Quote Link to comment Share on other sites More sharing options...
albertop Posted September 22, 2004 Author Report Share Posted September 22, 2004 Thanks guys, I think I will go with the 500k pots, I don´t quite undestand the procedureyou talk about Lovekraft, but thanks a lot for the advice. Quote Link to comment Share on other sites More sharing options...
mattdowney Posted September 22, 2004 Report Share Posted September 22, 2004 Matt, no offense, but try to stay with the group here. Did you not read this? My problem id that here in my country I can only get extremely low quality pots Somehow, I don't think Alberto has the option of scooting down to the Guitar center for new pots. hahahahhahah i am a idiot! sorry i guess i never read that! umm, i guess you will have to modify the pot! Quote Link to comment Share on other sites More sharing options...
lovekraft Posted September 23, 2004 Report Share Posted September 23, 2004 ...I don´t quite undestand the procedureyou talk about Lovekraft... Take a look at this diagram: Simply wire a 500k fixed resistor between 1 and 3, and then wire the pot normally. Quote Link to comment Share on other sites More sharing options...
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