sjaguar13 Posted January 3, 2004 Report Posted January 3, 2004 I have an Ibanez I want to put a Seymour Duncan in, but the wires aren't the same. The Ibanez is a bare wire to the bottom of a pot, a red wire to 5 way switch, and a white wire to 5 way switch. The SD has red, white, green, and black. If red and white were the same, and green was ground, then what do I do with black, hot output? The Ibanez has 2 humbucks, 1 volume, 1 tone, and a 5 way switch. All 8 pins on the switch have at least one wire, unlike the SD schematic for the 2 humbuckers. Quote
Scott Rosenberger Posted January 3, 2004 Report Posted January 3, 2004 The green and bare wires go together and go to the back of the pot. the red and white wires go together and go where the white wire is on the switch and the black wire goes where the red wire is on the switch Quote
sjaguar13 Posted January 4, 2004 Author Report Posted January 4, 2004 Thanks! It makes sound, but I am still having problems Quote
MikeB Posted January 4, 2004 Report Posted January 4, 2004 the seymore site may have some info on it.... Quote
Southpa Posted January 4, 2004 Report Posted January 4, 2004 This should help sort which wires go where. http://www.hotrodguitars.com/WireCode.htm And is this the schematic you are referring to? The black will be your hot output. Red and white gives you the option to split your HB into single coils. Hooking them together will just complete the series, pickups end to end, without the single coil option. http://www.seymourduncan.com/website/suppo...ay-w-split.html Quote
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