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Dc bias cap in tone circuit?


Diablothecat

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Applying DC to a capacitor doesn't change its capacitance. Its value is constant irrespective of the applied voltage across its terminals. 

Your circuit looks a little like a capacitance multiplier, but the implementation looks odd. Normally a cap multiplier circuit increases the apparent capacitance by the gain of the transistor (hFe) and can't be adjusted by a resistor. In your circuit all the pot is doing is providing a variable resistance for AC signals (ie the guitar signal) to bypass the cap/transistor through the battery. I'm not even sure the transistor will even be doing anything as the base appears to be grounded.

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I redrew schematic and got rid of the transistor instead going with switch, which is meant to discharge cap (if i applied lets say 5vdc and wanted to go lower i would need to discharge it) and from what i read here it should work:

https://www.murata.com/en-eu/support/faqs/capacitor/ceramiccapacitor/char/0005

R1 is there just to limit current, P1 is to change dc voltage to cap. I think it should work but if im wrong please correct me

0005_img0001.PNG

05afe8fb-8e1c-4dd1-b4cd-432eb4353930.jpg

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Interesting - I wasn't aware of that phenomena, although it appears to be largely a property of multi-layer ceramic capacitors with particular dielectrics.

P1 won't alter the voltage to the cap. The capacitor will still charge to whatever the voltage of the battery is; it will just change how quickly it gets there.

You shouldn't need S1/R1 to get the cap to discharge to a lower battery voltage. The cap should follow the battery to whatever voltage it is set to (notwithstanding my observation that P1 won't adjust the battery voltage).

Where does 'in' and 'out' connect to in the guitar?

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